How to Convert Liters to Milliliters

The liter and the milliliter are both key units of volume in the metric system. The method for converting liters to milliliters is demonstrated in this worked example problem. How Many Milliliters in a Liter? The key to working a liter to milliliter problem (or vice versa) is to know the conversion factor. There are 1000 milliliters in each liter. Because this is a factor of 10, you dont actually have to break out the calculator to do a conversion. You can simply move the decimal point. Move it three spaces to the right to convert liters to milliliters (e.g., 5.442 L 5443 ml) or three spaces to the left to convert milliliters to liters (e.g., 45 ml 0.045 L). Problem How many milliliters are in a 5.0-liter canister? Solution 1 liter 1000 mL Set up the conversion so the desired unit will be canceled out. In this case, we want mL to be the remaining unit. Volume in mL (Volume in L) x (1000 mL/1 L) Volume in mL 5.0 L x (1000 mL/1 L) Volume in mL 5000 mL Answer There are 5000 mL in a 5.0-liter canister. Check your answer to make sure it makes sense. There are 1000 times more milliliters than liters, so the milliliter number should be much greater than the liter number. Also, since we are multiplying by a factor of 10, the value of the digits wont change. Its only a matter of moving the decimal point.

Advanced Dermatology And Cosmetic Surgery - 807 Words

I am writing to inform you of your clinic’s participation in an exciting, new patient satisfaction trial. Advanced Dermatology Cosmetic Surgery has teamed up with the marketing and research group xAmplifier to begin capturing and analyzing patient feedback across select ADCS branches. If successful, this program will be expanded to our entire organization later this year. The trial was inspired by our desire to better understand what motivates patients to choose Advanced Dermatology Cosmetic Surgery over our competitors, how customer satisfaction fluctuates at the various stages of treatment, and reveal areas for growth and improvement in our communication, staff training, services, and practices. We believe that patients choose Advanced Dermatology Cosmetic Surgery not only for the quality, thoroughness, and convenience our our treatments, but for the warmth, compassion, and confidence instilled in our patients by each of you, the ADCS staff. 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Risks Analysis for Charity Fashion Show

Question: Describe about the Risks Analysis for Charity Fashion show? Answer: Risks Analysis for Charity Fashion show There are various kind of risk could be occur before/during any fashion show. There are below risk we identify as below: Factors involve cost were ignored: There are certain factors were ignored which accessing the cost of overall show like cost for printing materials used for advertizing. Show Venue Capacity: The venue is shortlisted just having capacity of 250 whereas if the number of visitors is more there is no space. We should take an account of at least 15% more capacity of venue as compared to tickets. Rasing of fund 10000: At the time of booking it was not considered that to raise a fund of 10000 required to sell approx 300 tickets at an average cost price of 25. It was not considered. Theme of Fashion show: Chosen theme was an 80s theme which is a popular theme for fancy dress parties not for the fashion shows so there could be risk of selling all tickets. Models availability: There is an identified risk of availability of 10 Models ,There could be the scenarios that Models who are popular among the UK will not be available for charity events or may de date will not suits them. Additional cost (Cost Overrun): There is also risks to collect additional cost along with the target of 10000 .Some of additional cost are as below: Average price of Hair makeup needs 30-50 so it can add an additional cost of 300- 500. Average price of Outfits from ASOS needs 30-50 so it can add an additional cost of 300- 500. Average price of Outfits from 80s online store needs 30-50 so it can add an additional cost of 300- 500. Average price of Comical Outfits needs 30.so it can add an additional cost of 300. Average price of Outfits from ebay needs 13 so it can add an additional cost of 130. Additional cost of Table 150 and chair 450 required for sitting arrangements of 200 people. Cost for security adds 49.75 for at least 3 guards. Cost of Marquee for 200 people adds 700. Cost of food catered during the events adds 900. Resources Availability: As this is a big event so all resources should be available all the time during and and post the event to make a success. We observe that Rameez Abbasi who was responsible for advertizing was not coming to meeting on regular basis. This could be impact the event and create issues in success of the event. Children on site There is a risk of loss of contact of children on site due to crowd. It should also be need to provide guidance to staff for caring lost children. Exit Blockage: There is a risk of blockage during exit of event due to people will rushing to come out from the venue. Electrocution: There is a risk of Electrocution due to any short circuit or over supply of current in system. Fire This is also a kind of risk may occur from various reasons like Electrocution or smoking. Food Quality We have used multiple vendors to cater food during the event so there could be a risk of food quality. If quality of food is not good it will impact the health of visitors. Vehicle Movements Due to heavy rush there could be vehicle collision may happen. So avoid such saturations we need extra personal to help people in entering and exiting from venue with their vehicles. Fund management As this event happened to generate fund and all collected profit from this fund will be used in cancer research. It is essential to assign a person who holds all the inflow and outflow of the fund so that at the end we could measure the profile generated from this event. Government guidelines to be follow For every Charity event there are some government guidelines need to be follow so that for any disputes may be resolved as per guidelines provided from government. Out of these Risks most of critical risks are cost overrun, Model availability, venue capacity, Food Quality and resource availability. Mitigate Approach: To mitigate Cost overrun we need to sell extra tickets and also auction of designer clothes used during fashion show and also get money from selling events pics online. Model availability can be mitigating to giving chance to upcoming Models instead of all famous Models. Venue capacity can be mitigate by booking a large space. Food Quality can be achieved by assign a person who test every food that cater to visitors during the event. Resource availability should be achieved by setup backup resource for every area so in case on resource crunch we can utilize extra resource.Risk Assessment matrix Risk Affected person Severity of risk Proposed solution Children on site All persons on site, especially children. Medium 1. Mobile telephone number of teacher / head of group taken so that they can be contacted if a child is lost or separated. 2. Children only to be handed over to a clearly recognized parent//guardian/teacher/head of group. 3. Staff briefed on procedure for caring for lost children Clearing visitors from Show at show close Exhibitors, Visitors Low 1. Repeated announcements are made on the speakers asking visitors to leave the show; 2. Restocking of stands starts 15 minutes after the close of the show to allow visitors to leave before this activity begins; 3. Security personnel move through show to encourage visitors to leave. Electricity supplies on stands All persons on site Low 1. All installations to be inspected by CANCER RESEARCH appointed Electrical Safety Inspector before being energized; 2. All installations will be carried out by the Official Electrical contractor for the show, Melville Electrical; 3. Where possible all electrical cables buried in outside areas to avoid trip hazards. Where this is not possible, cables are to be covered using ramps. Food Quality Exhibitors, Organizers, Visitors, Security and Staff Low 1. Environmental Health and Trading Standards Advice on Food Safety communicated where required. 2. CANCER RESEARCH has sole rights for the sale or distribution of any food or drink. Any exhibitors wishing to sell or distribute food or drink have to apply for permission to the CANCER RESEARCH ; Vehicle Movements All on Site Medium 1. All movements of vehicles to be controlled by the CANCER RESEARCH Traffic Department, and CANCER RESEARCH Security. 2. Defined routes for exhibitors and visitors pre-planned by CANCER RESEARCH traffic department, CANCER RESEARCH Security and Organizers. Fire All persons on site Low 1.Introduce passive fire drills (ie randomly get each member of staff to explain fire evacuation procedures and assembly point location record date against the staff name when correct answers were given). Fund management Organizers Medium Assign a spoc to manage funds Additional cost (Cost Overrun) Organizers High Adding extra tickets to sell Fashion Theme Low Theme can be select from online and offline survey. Venue Capacity Organizers, Visitors Medium By accruing big area venue Availability of Models Organizers Medium Give chance to some of starters in modeling area instead to use all famous models.

Oconnors Wise Blood Essays - Bereshit, Wise Blood, Enoch, Repentance

O'connor's Wise Blood I am not sure how to react to the novel after reading it. It has been a very confusing novel; I am not quite sure what it is saying about religion. Initially I thought that it was supporting an anti-religious aspect of life. However, the end of the novel presented a twist though the eyes of Mrs. Flood, which made me change my initial thoughts about it, turning it into a novel that seemed to say, this is what happens if you do not believe in Christianity. The novel also presented the atmosphere of the American City as a trap; an inescapable place that drains all morals, leaving one surround by a society of loneliness. The novel consisted of two different stories, one about Hazel Motes and one about Enoch Emery. Both stories, in my eyes, were quite different. The story involving Hazel Motes involved something that he had been struggling with for most of his life - purity, religion, and guilt, which I believe, was brought about by his mother. This information is given when he is in bed with Mrs. Watts and recalls a memory of when his mother told him that Jesus died to redeem him. Motes's response to this was, I never ast him. However, even after his beating, Motes feels that he must repent more by walking a mile with stones in his shoes, thinking that there will be a sign from Him. Perhaps it was this incident that led to his disbelief, waiting for a sign that never came. His mother seems to be someone that he both cherishes and hates. The bible and the pair of glasses show this. He feels that he must carry both her Bible and her pair of glasses around with him, although he disbelieves everything that she believed in. Although he says that he is keeping the bible because it reminds him of home and the glasses incase he ever looses his vision, I feel that he is keeping them to hold on to a piece of his mother; a piece of Jesus. The last chapter helped me to form a sort of understanding. I felt that I could relate to Mrs. Flood. I felt like the questions that she kept raising to and about Motes were questions that I would have been raising. For the most part, they were many of the questions that I kept raising though out the novel. There was one question in particular that she raised that has kept me wondering if Motes ever received his redemption. How would he know if time was going backward or forward or if he was going with it? It made me wonder if he blinded himself as a form of repentance. I thought that maybe he stopped preaching and was torturing himself for Jesus, but then when Mrs. Flood asks him about his preaching he says, If you believed in Jesus, you wouldn't be so good. If he were trying to repent, why would he say that? The story about Enoch Emery seemed to be a whole different story all together. His story seemed to be one about a boy who had been rejected all of his life, cast into a city that trapped and destroyed him. In a strange way, the city that he was forced to live in turned him, his personality and his appearance (gorilla suit), into an animal. The animal that he became was similar to the animals that he had to visit everyday; the animals that he hated. Chapter 12 presents a descriptive image of what the American City had done to Enoch Emery. He had the sense that he was setting off to get some honor, but he was very nervous, as if he were afraid he might have to snatch it instead of receive it. This is exactly what became of Enoch Emery; he became an animal that had to snatch everything that came to him in a city were people ain't friendly. Both Motes and Emery were young men looking for acceptance and piece of mind in a city filled with corruption, whoring, false preaching, and very few morals. They were outsiders, driven to insanity by a world that did

The Hoplite Revolution and Greek Warfare essays

The Hoplite Revolution and Greek Warfare essays One of the social issues around 356 BC- 400 BC was warfare in Ancient Greece. For the Greeks war was more than tactics, strategy and blood; it was linked to almost every aspect other social organization. Greeks warfare displayed the honesty of two armies facing each other head on in broad daylight. The soldiers were called hoplites. The heavily armed hoplite of the fighting unit wore bronze armor on his shins and chest and a bronze helmet slit with a narrow opening for eyes and mouth. He carried a heavy wooden shield in his left hand. His weapon a pike; a heavy wooden, iron tipped thrusting spear at least 9 feet long; and a short, iron stabbing sword. A hoplites panoply weight range from fifty to seventy pounds. The solid bronze helmet that the average hoplite wore weighed approximately five pounds and covered the head and parts of the face and neck. The solid headpieces also provided no ventilation, often times leading to dehydration. The men in the phalanx were lined up in rows; usually four to eight rows deep. The phalanx was positioned usually near a mountain. If there were no mountain they would usually be lined up between two rivers. The phalanx formation called for each man to trust his neighboring infantryman often times a friend or a relative. With a shield in his left hand and a spear in his right, each man dependent on his fellow hoplites shield for full body coverage. Battles were won and lost depending on the phalanxs ability to hold its formation. Every hoplite helped, they all worked together. There was no individual hero. If a hoplite went individually he would die very quick. It was very important to keep the chain together. It was also very dangerous to trip and fall, because your fellows would walk over you. One weak link in the chain of infantryman could create a gap that was potentially fatal if exploited. For this reason, the younger hoplites with some experience were place ...

The Easy Guide to the 30-60-90 Triangle

The Easy Guide to the 30-60-90 Triangle SAT / ACT Prep Online Guides and Tips Acute, obtuse, isosceles, equilateral†¦.When it comes to triangles, there are many different varieties, but only a choice few that are â€Å"special.† These special triangles have sides and angles which are consistent and predictable and can be used to shortcut your way through your geometry or trigonometry problems. And a 30-60-90 triangle- pronounced â€Å"thirty sixty ninety†- happens to be a very special type of triangle indeed. In this guide, we’ll walk you through what a 30-60-90 triangle is, why it works, and when (and how) to use your knowledge of it. So let’s get to it! What Is a 30-60-90 Triangle? A 30-60-90 triangle is a special right triangle (a right triangle being any triangle that contains a 90 degree angle) that always has degree angles of 30 degrees, 60 degrees, and 90 degrees. Because it is a special triangle, it also has side length values which are always in a consistent relationship with one another. The basic 30-60-90 triangle ratiois: Side opposite the 30 ° angle: x Side opposite the 60 ° angle: x * √3 Side opposite the 90 ° angle: 2x For example, a 30-60-90 degree triangle could have side lengths of: 2, 2√3, 4 7, 7√3, 14 √3,3, 2√3 (Why is the longer leg 3?In this triangle, the shortest leg (x) is √3, so for the longerleg, x√3 = √3 *√3 = √9 = 3. And the hypotenuse is 2 times the shortestleg, or 2√3) And so on. The side opposite the 30 ° angle is always the smallest, because 30 degrees is the smallest angle. The side opposite the 60 ° angle will be the middle length, because 60 degrees is the mid-sized degree angle in this triangle. And, finally, the side opposite the 90 ° angle will always be the largest side (the hypotenuse) because 90 degrees is the largest angle. Want to get better grades and test scores? We can help. PrepScholar Tutors is the world's best tutoring service. We combine world-class expert tutors with our proprietary teaching techniques. Our students have gotten A's on thousands of classes, perfect 5's on AP tests, and ludicrously high SAT Subject Test scores. Whether you need help with science, math, English, social science, or more, we've got you covered. Get better grades today with PrepScholar Tutors. Though it may look similar to other types of right triangles, the reason a 30-60-90 triangle is so special is that you only need three pieces of informationin order to find every othermeasurement. So long as you know the value oftwo angle measures and one side length (doesn’t matter which side), you know everything you need to know about your triangle. For example, we can use the30-60-90 triangle formula tofill in all the remaining information blanks of the triangles below. Example 1 We can see that this is a right triangle in which the hypotenuse is twice the length of one of the legs. This means this must be a 30-60-90 triangle and the smaller given sideis opposite the 30 °. The longer leg must, therefore, be opposite the 60 ° angle and measure 6 *√3, or 6√3. Example 2 We can see that this must be a 30-60-90 triangle because we can seethat this is a right triangle with one given measurement, 30 °. The unmarked angle must then be 60 °. Since 18 is the measure opposite the 60 ° angle, it must be equal to x√3. The shortest leg must then measure $18/√3$. (Note that the leg lengthwill actually be $18/{√3} *{√3}/{√3} = {18√3}/3 = 6√3$ because adenominator cannot contain a radical/square root). And the hypotenuse will be $2(18/√3)$ (Note that, again, you cannot have a radical in the denominator, so the final answer will really be 2 times the leg length of 6√3= 12√3). Example 3 Again, we are given two angle measurements (90 ° and 60 °), so the third measure will be 30 °. Because this is a 30-60-90 triangle and the hypotenuse is 30, the shortest leg will equal 15 and the longer leg will equal 15√3. No need to consult the magic eight ball- these rules always work. Why It Works: 30-60-90 Triangle Theorem Proof But why does this special triangle work the way it does? How do we know these rules are legit? Let’s walk through exactly how the 30-60-90 triangle theorem works and prove why these side lengths will always be consistent. First, let’s forget about right triangles for a second and look at an equilateral triangle. An equilateral triangle is a triangle that has all equal sides and all equal angles. Because a triangle’s interior angles always add up to 180 ° and $180/3 = 60$, an equilateral triangle will always have three 60 ° angles. Now let's drop down a height from the topmost angle to the base of the triangle. We've now created two right angles and two congruent (equal) triangles. How do we know they’re equal triangles? Because we dropped a height from an equilateral triangle, we’ve split the base exactly in half. The new triangles also share one side length (the height), and they each have the same hypotenuse length. Because they share three side lengths in common (SSS), this means the triangles are congruent. Note: not only are the two triangles congruent based on the principles of side-side-side lengths, or SSS, but also based on side-angle-side measures (SAS), angle-angle-side (AAS), and angle-side-angle (ASA). Basically? They're most definitely congruent. Now that we’ve proven the congruencies of the two new triangles, we can see that the top angles must each be equal to 30 degrees (because each triangle already has angles of 90 ° and 60 ° and must add up to 180 °). This means we have made two 30-60-90 triangles. And because we know that we cutthe base of the equilateral triangle in half, we can see that the side opposite the 30 ° angle (the shortest side) of each of our 30-60-90 triangles is exactly half the length of the hypotenuse. So let us call our original side length x and our bisected length $x/2$. Now all that leaves us to do is to find our mid-side length that the two triangles share. To do this, we can simply use the pythagorean theorem. $a^2 + b^2 = c^2$ $(x/2)^2 + b^2 = x^2$ $b^2 = x^2 - ({x^2}/4)$ $b^2 = {4x^2}/4 - {x^2}/4$ $b^2 = {3x^2}/4$ $b = {√3x}/2$ So we're left with: $x/2, {x√3}/2, x$ Now let's multiply each measure by 2, just to make life easier and avoid all the fractions. That way, we're left with: x, x√3, 2x We can see, therefore, that a 30-60-90 triangle will always have consistent side lengths of x, x√3, and 2x (or $x/2$, ${√3x}/2$, and x). Luckily for us, we can prove 30-60-90 triangle rules true without all of...this. When to Use30-60-90 Triangle Rules Knowing the30-60-90 triangle rules will be able to save you time and energy on a multitude of different math problems, namely a wide variety of geometry and trigonometry problems. Geometry Proper understanding of the 30-60-90 triangles will allow you to solve geometry questions that would either be impossible to solve without knowing these ratio rules, or at the very least, would take considerable time and effort to solve the "long way." With thespecial triangle ratios, you can figure out missing triangle heights or leg lengths (without having to use the pythagorean theorem), find the area of a triangle by using missing height or base length information, and quickly calculate perimeters. Any time you need speed to answer a question, remembering shortcuts like your 30-60-90 rules will come in handy. Trigonometry Memorizing and understanding the 30-60-90 triangle ratio will also allow you to solve many trigonometry problems without either the need for a calculator or the needto approximate your answers in decimal form. A 30-60-90 triangle has fairly simple sines, cosines, and tangents for each angle (and these measurements will always be consistent). Sine of 30 ° will always be $1/2$. Cosine of 60 ° will always be $1/2$. Though the other sines, cosines, and tangents are fairly simple, these are the two that are the easiest to memorize and are likely to show up on tests. So knowing these rules will allowyou to find these trigonometry measurements as quickly as possible. Tips for Remembering the30-60-90 Rules You know these30-60-90 ratio rules are useful, but how do you keep the information in your head? Remembering the30-60-90 triangle rules is a matter of remembering the ratio of 1: √3: 2, and knowing that the shortest side length is always opposite the shortest angle (30 °) and the longest side length is always opposite the largest angle (90 °). Some people memorize the ratio by thinking,â€Å"x, 2x, x√3,† because the â€Å"1, 2, 3† succession is typically easy to remember. The one precaution to using this technique is to remember that the longest side is actually the 2x, not the x times √3. Another way to remember your ratios is to use a mnemonic wordplay on the 1: root 3: 2 ratio in their proper order. For example, â€Å"Jackie Mitchell struck out Lou Gehrig and ‘won Ruthy too,’†: one, root three, two. (And it's a true baseball history fact to boot!) Play around with your own mnemonic devices if these don’t appeal to you- sing the ratio to a song, find your own â€Å"one, root three, two† phrases, or come up with a ratio poem. You can even just remember that a 30-60-90 triangle is half an equilateral and figure out the measurements from there if you don't like memorizing them. However it makes sense to you to rememberthese 30-60-90 rules, keep those ratios your head for your future geometry and trigonometry questions. Memorization is your friend, however you can make it happen. Want to get better grades and test scores? We can help. PrepScholar Tutors is the world's best tutoring service. We combine world-class expert tutors with our proprietary teaching techniques. Our students have gotten A's on thousands of classes, perfect 5's on AP tests, and ludicrously high SAT Subject Test scores. Whether you need help with science, math, English, social science, or more, we've got you covered. Get better grades today with PrepScholar Tutors. Example 30-60-90 Questions Now that we've looked at the hows and whys of 30-60-90 triangles, let's work throughsome practice problems. Geometry A construction worker leans a 40-foot ladder up against the side of a building at an angle of 30 degrees off the ground. The ground is level and the side of the building is perpendicular to the ground. How far up the building does the ladder reach, to the nearest foot? Without knowing our 30-60-90 special triangle rules, we would have to use trigonometry and a calculator to find the solution to this problem, since we only have one side measurement of a triangle. But because we know that this is a special triangle, we can find the answer in just seconds. If the building and the ground are perpendicular to one another, that must mean the building and the ground form a right (90 °) angle. It’s also a given that the ladder meets the ground at a 30 ° angle. We can therefore see that the remaining angle must be 60 °, which makes this a 30-60-90 triangle. Now we know that the hypotenuse (longest side) of this 30-60-90 is 40 feet, which means that the shortest side will be half that length. (Remember that the longest side is always twice- 2x- as long as the shortest side.) Because the shortest side is opposite the 30 ° angle, and that angle is the degree measure of the ladder from the ground, that means that the top of the ladder hits the building 20 feet off the ground. Our final answer is 20 feet. Trigonometry If, in a right triangle, sinÃŽËœ = $1/2$ and the shortest leg lengthis 8. What is the length of the missing side that is NOT the hypotenuse? Because you know your 30-60-90 rules, you can solve this problem without the need for either the pythagorean theorem or a calculator. We were told that this is a right triangle, and we know from our special right triangle rules that sine 30 ° = $1/2$. The missing angle must, therefore, be 60 degrees, which makes this a 30-60-90 triangle. And because this is a 30-60-90 triangle, and we were told that the shortest side is 8, the hypotenuse must be 16 and the missing side must be 8 * √3, or 8√3. Our final answer is 8√3. The Take-Aways Remembering the rules for 30-60-90 triangles will help you to shortcut your way through a variety of math problems. But do keep in mind that, while knowing these rules isa handy tool to keep in your belt, you can still solve mostproblems without them. Keep track of the rules of x, x√3, 2x and 30-60-90 in whatever way makes sense to you and try to keep them straight if you can, but don't panic if your mind blanks out when it's crunch time. Either way, you've got this. And, if you need more practice, go ahead and check out this 30-60-90 triangle quiz. Happy test-taking!

CMG301 MOD 3 CA Essay Example | Topics and Well Written Essays - 500 words

CMG301 MOD 3 CA - Essay Example On receipt of the customers’ notice of dissatisfaction, the contractor will first attempt to resolve any outstanding issues directly with the customer. If this does not resolve the customers’ complaints, the matter will be referred to the State of Washington Contractors’ Association for mediation. Only if this does not resolve the matter are the parties free to litigate their differences. Unless otherwise agreed to by the contractor, the remaining $750 must be paid within 30 days of the customers’ acceptance of the work. 2) The remaining $500 still owing must then be paid in 5 consecutive monthly installments, with the first one due within 60 days of work completion and receipt of a final invoice. These deferred payments are subject to a 10% interest charge payable with the first installment. Therefore the deferred payments will be $100 each, with the exception of the first one which will be $150. The deferred payments including interest will be $550 and under this plan the total cost of the contract will be $1050. If this option is accepted by the contractor, this will be confirmed by an amendment to the contract signed by both